If Ahmed used string and tied it to the Castle Rock point and labeled it as point “A” on paper it would be basically 2x + 6 paces. With this being the radius you will know that it is the same anyway you fit this from the circle. So to find the Treasure we will use “C”. Vanessa will use her compass to find north from Castle Rock. From there she will walk “X” paces in a straight line northward. At the end of her distance she will call this point “B”. Vanessa will now turn 90 degrees to the right and will walk 2x+4 paces east until she is at point “C”. We have now acquired a line segment which we will call AB which is basically the line from A to B, the line segment from B to C is considered BC. However, the lines AB and BC intersect to form a perpendicular angel, and we will use line AC as Ahmed’s route. The end state of the line segments if one was to draw them out would equal a triangle. With the face that Vanessa had turned in a 90 degree angle that makes this triangle a right angle ABC. Lines AB and BC are to be considered as the legs and we will think of AC as the…
because I realized that the lines O1O, O1O2, and O2O1, form a triangle, I realized that if that triangle was a right triangle I could find the distance between O1, and O. To prove that triangle OO1O2 is a right triangle I used the radii of O1, I realized that the sides of triangle PO1Q, O1P, and O1Q, are radii, and therefore they are equal. Since they are equal, the triangle PO1Q, is an isosceles triangle. In an isosceles triangle the base angles are congruent , so that means that angle Q is…
from the gods” and had stayed up pondering his options. Why would he have come to my house and arranged triangles from firewood? “It’s nothing.” I said quickly. “And it’s not a book. I can’t read.” That was a lie, I could read very well. “Go home. Why are you at my house anyways?” “Don’t burn the book.” Pythagoras warned me, and I got the message that he had seen it. “Daphne, when you’re done with…
the activity applies to Van Hiele’s level 1 which is the Visual Level because the children have to identify what shapes were used in the Ozella quilt. For example, “the students should be able to know that four squares are together to make crossroads or that squares and right triangle was used to a Bear’s Claw.” This concept applies to Van Hiele’s Level 2 which is the Descriptive and Relational level. In this level, the students will recognize or analyze figures by their properties or…
tree sides of a right triangle. It’s the sum of the areas of the two squares on the legs equals the area of the square on the hypotenuse. The equation use for it is A squared plus B squared equals C squared.The Theorem relates the lengths of the three sides of any right triangle. The theorem is named after the ancient Greek. There is evidence that indicates that Pythagorean Theorem was well- known to the mathematicians of the first Babylonian Dynasty (20th to 16th centuries BC) which would…
based learning activity for my student’s. How does it connect art with another discipline: My fourth graders have been learning about the Six Pillars of Characters and what each pillar stands for. The Six Pillars of Characters are Trustworthiness, Respect, Responsibility, Fairness, Caring, and Citizenship.(The Six) As a fun way for the students to show me what they have learned about the six different pillars, I will be incorporating role play into their final lesson on the Six Pillars of…
At about twenty centuries ago there was an amazing discovery about right angled triangles: “In a right angled triangle the square of the hypotenuse is equal to the sum of squares of the other two sides.” It is called Pythagoras Theorem and can be written in one short equation: a²+b²=c² where c is the longest side of triangle and a and b are the other two sides. Pythagoras was born in the island of Samos in 570 BC in Greek in the eastern Agean. He was the son of Mnesarchus and his mother's name…
the properties of right-angled triangles seems to be the most ancient and widespread mathematical development after basic arithmetic and geometry, and it was touched on in some of the most ancient mathematical texts from Egypt , dating from over a thousand years earlier. One of the simplest proofs comes from ancient China, and probably dates from well before Pythagoras' birth. It was Pythagoras, though, who gave the theorem its definitive form, although it is not clear whether Pythagoras himself…
These things don't exist in math. Math is full of "rules" that don't have exceptions. Things such as the Pythagorean Theorem will always work for right triangles. There will never be a right triangle where a^2 + b^2 does not = c^2. This is what I like about math. Math is a subject that I think would never Let me down ; It has no contradictions. It's something that's reliable and useful. I've learned that without math, life would be a cycle of events without reason. If I ever wonder why when I…
I'm not exactly sure how to solve this question I might have forgot how to do it but I'm going to guess that based off the picture & what I know about circles I can say that all circles if this makes sense are always similar to each other & that's always no matter what the radius might be ' The steps are as follows... * Obviously draw a triangle * Insert angle bisector for each angle of the tri. Insert the lines & make sure that your long to the point where you can see the point of…