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7 Cards in this Set
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Limit
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Let f:D R be a function with D in R, xo in R is an accupoint of D. Moreover, let L be in R. We say f(s) has a limit L at xo iff the following holds:
-For every positive real number E, there exists a positive real d, such that whenever x is in D\{xo}, with |x-xo|<d, we have |f(x)-L|<E. |
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Sub-sequence
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Let (an)(n in N) be a sequence and (nk)(k in N) be a sequence of positive integers such that n1<n2<n3<…<nk. The sequence (nk) is called a subsequence of (an).
In other words: deleting some or none of the terms from a sequence and renaming the remaining terms, with remaining terms in the same order as in the sequence. There are still infinitely many terms after some are deleted. |
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Increasing
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sequence (an)(n in N) is increasing iff an<=an+1 for all positive integers
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decreasing
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Decreasing: a sequence is decreasing iff an>=an+1 for all positive integers n.
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Monotone
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a sequence is either increasing or decreasing
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Summary of proofs with lim arithmetic
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Take arbitrary sequence that converges to x0
Use thm 16lim(fxn)=A Use some other rule for lim seq Use thm 16 in other direction |
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Summary of proofs with convergent arithmetic
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Set up convergent definition of an and bn with N1 and N2
(For multiplication add |an|<=M bounded) (For division |bn|>c by lemma) Define E 1. For addition-E=E/2 2. For multiple-E’=E/(/(|B|+M)>0 3. For division-E=|B|E*c N=max(N1,N2) and then put everything together Will use triangle inequality |