- Shuffle
Toggle OnToggle Off
- Alphabetize
Toggle OnToggle Off
- Front First
Toggle OnToggle Off
- Both Sides
Toggle OnToggle Off
Front
How to study your flashcards.
Right/Left arrow keys: Navigate between flashcards.right arrow keyleft arrow key
Up/Down arrow keys: Flip the card between the front and back.down keyup key
H key: Show hint (3rd side).h key
![]()
PLAY BUTTON
![]()
PLAY BUTTON
![]()
19 Cards in this Set
- Front
- Back
|
Poynting Vector
|
-The rate and direction in which an electromagnetic wave is transporting energy per unit area is described by a vector S
-Always perpendicular to both E and B, and has magnitude EBsin(theta) |
|
Visible Light Spectrum
|
390*10^-9m --> 700*10^-9m
|
|
Index of Refraction
|
Compares the speed c of light in a vacuum to the speed v of light in a medium
n = c/v |
|
Indices of Refraction for water and glass:
|
1.3, 1.5
|
|
Snell's Law
|
n1*sin(theta1) = n2*sin(theta2)
|
|
When light crosses into a new medium, the frequency ________ and the wavelength _____
|
same, changes
|
|
If the medium's n is higher, the wavelength ________
|
becomes shorter
|
|
Energy of a single photon
|
E = hf
|
|
Critical Angle
|
If the angle of incidence is large enough, the entire amount of photons will be reflected at the angle of refraction (angle of refraction = 90 degrees in snell's law)
|
|
Longer wavelengths move __________ through a medium
|
faster
|
|
Virtual Image
|
Doesn't actually exist outside the mind of the observer; no light rays emanate from the virtual image
|
|
If the center is thicker at its ends, it will _________ light
|
converge
|
|
Focal Length of a mirror:
|
f(mirror) = (1/2)*r
r = radius of curvature |
|
What is the focal point of a lens affected by?
|
The refractive indices of the lens and the medium that the lens is in. Also, by the radii of curvature of both sides of the lens.
|
|
Power (P)
|
P = 1/f
in units of m^-1 |
|
Lateral Magnification
|
The ratio of the size of the image to the size of the object
m = -(di/do) = (hi/ho) |
|
Angular Magnification
|
The angle occupied by the object (theta1) when at the near point, compared to the angle occupied by an image (theta2) of the object when in front of a lens
m(theta) = (theta2)/(theta1) |
|
Thin Lens Equation
|
(1/f) = (1/do) + (1/di)
|
|
Read Pages 152-155
|
Physics, lecture 8, light and optics
|