Bag A stimulates cell whose contents are hypotonic to its environment. The situation is because the concentration of the dissolved substances in the cell is less than the surrounding media. In this case, the cell contents contain 1% sucrose solution that is less concentrated than the 50% surrounding media. Therefore, a large concentration gradient develops between the two media. Consequently, because of the high concentration gradient, the bag loses water faster and this leads to its reduction in volume. The Pressure in the bag reduces due to a loss of volume of the solvent. A point reaches whereby the pressure on the outwards side of the tubing equal to the force driving the water out of the tube. At this point, no more osmosis occurs in the bag (Wisniak, 2013).
Bag B stimulates a cell whose contents are isotonic to its surrounding environment. This situation arises because the concentration of the bag contents is 1% sucrose concentration that resembles the solute concentration on the outside. There is no concentration gradient created, and thus no changes noted in the weight of the bag. …show more content…
The sucrose concentrations in bags C and D is 25% and 50%. These solutions are more concentrated than the surrounding 1% sucrose concentrations. Thus, concentration gradients exist between the two Medias. As a result, the two bags begin gaining water. The bag C gains the solvent at a slower rate than by the bag D. The reason is that the concentration gradient in bag D is higher than that in the bag. The consequent gain of water dilutes the concentration of the solutions inside the bags thus balancing pressures on both sides of the two bags. The osmosis process comes to an end in the two bags (Kucera,