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D block elements

Series of elements formed by progressive filling of 3d, 4d, 5d shells of electrons


Aka transition elements

Transition metals: old and IUPAC definition

D block elements are known as TM's because their properties are transitional between those of s block and p block elements.



New definition by IUPAC;


Transition metals are metals having incomplete d subshell (either in ionic form or neutral atom)

Name three d block elements that are non transition metals

Zinc, Cadmium, mercury of G12


Why are Zn, Cd, and Hg non transition metals

Because their d subshells are completely filled in both their ground state as well as common oxidation states.


d¹⁰ configuration

Transition metals definition and props

Transition metals are metals having incomplete d subshell either in ground state or excited state(most common OS)



Special character: d orbitals of Transition metals protrude to periphery of atom MORE than other orbitals. => Thus, more influenced by surroundings AND affect surrounding atoms or molecules.



Propertie

Properties shown by Transition elements

(typical metallic properties)


• metallic lustre


•malleability and ductility


•thermal and electric conductivity


•low volatility


•hard and high tensile strength


•high MP and BP


Transition metals have high melting and boiling points. Why?

High Melting points of these metals are attributed to the involvement of greater number of electrons from (n-1)d subshell in addition to na electrons in interatomic metallic bonding. (Because we know that energy diff between (n-1)d subshell and ns shell is very low due to low shielding effect of d orbitals)


Variation of melting point across series (ATP) (3d series)

In any row, MP's of these metals rise to a maximum at d⁵ except for anomalous values of Mn and Tc.



And fall regularly as atomic number increases.

Variation of enthalpy of atomisation

TM's have high enthalpies of atomisation


Variation resembles that of melting point.


The maxima at about the middle of each series indicates that enthalpy of atomisation is directly related to the number of unpaired electrons.


Unpaired electrons in d subshell are favourable for strong interatomic interaction.


Greater the number of unpaired electrons, stronger is the resultant bonding.


Metals of 2nd and 3rd series have greater ∆aH = explains why there is much more frequent metal-metal bonding in compounds of heavy TM's

Why do heavier transition metals have much more frequent metal-metal bonding?

Because they have greater enthalpies of atomisation

General trend of ionic and atomic radii

• progressive decrease in radius with increasing atomic number.


Reason: each time the nuclear charge increases by unity, a new electron enters a d orbital


{ Also, shielding effect of d electron is NOT that effective, thus effective nuclear charge increases along the series and ionic radius decreases ATP.}

Variation of atomic radii

•Variation within a series is quite small


• comparison of atomic size of 1 series compared to those of corresponding elements in other series:


There's an increase in atomic size from corresponding elements of 3d series to those of 4d series .


BUT----corresponding radii of elements of 4d and 5d series are virtually the same.

Reason why atomic radii of elements of 5d series and those of corresponding elements from 4d series are the same

Before the 5d series of elements begin, the filling of 4f orbitals must take place (which happens in the lanthanide series) which results in greater-than-expected decrease in ionic radii of elements in lanthanide series(due to poor sheilding effect of 4f electrons). (In one word, lantanoid contraction)

Lanthanoid contraction

It's the greater-than-expected decrease in ionic/atomic radii of elements in lanthanide series due to low shielding effect of 4f electron.



This can explain why the radii of elements of 4d and those of corresponding elements of 5d are virtually the same.(before 5d series begins, filling of 4f subshell must take place, which results in smaller than otherwise expected ionic radii for 5d series)

Variation of IE across the series and causes of irregularity

Obviously, IE¹ increases (only slightly) along the series with increase in atomic number because of increase in Z effective. (Slightly because atomic radii decrease less rapidly due to shielding of d orbitals towards 4s electrons)


.


There are irregularities in the trend though. That can be mainly attributed to loss of exchange energy.Loss of exchange energy is responsible for greater stability of ions/ atoms having completely filled subshell (d¹⁰) followed by half filled subshells (e.g. elements/ions having d⁵ configuration).


Loss of exchange energy is responsible for greater stability of ions/ atoms having completely filled subshell (d¹⁰) followed by half filled subshells (e.g. elements/ions having d⁵ configuration).


.


Trend of IE² and IE³

General trend of increasing values of IE² as Zeff increases


General trend because it isn't complicated by shielding of s electrons by d electrons anymore (since M² and M³ ions have d* configuration)



•Trend of steady increase in IE² is broken for formation of Mn²


Trend of steady increase in IE³ breaks for formation of Fe ³

We expect IE² to increase from Cr to Mn, but that doesn't happen.


Exbulainexbulainblease

S¹: write the electronic configurations of Mn¹+ and Cr¹+.


S²: state which one has a stable configuration and claim 'loss of exchange energy' and 'more stability' and state 'which one is harder to ionise' as the reason for that.

Explain why IE³ of Fe is < that of Mn

Same reasons. STOP BEING LAZY AND TRY IT OUT!

IE² exceptions/irregularities in trend

Second ionisation enthalpies have unusually high values for Cr and Cu (where M+ ions have d⁵ and d¹⁰ configurations. Thus, it's harder to ionise them)


•IE² for Zinc is correspondingly low because ionisation of Zn+ results in stable d¹⁰ configuration.


IE³ specialities in trend

• are Quite high


high values for third ionisation enthalpies of Co, Ni, and Zn . (Possible reasons as for why it's difficult to obtain OS greater than 2 for these elements)

Trends in Electrode potential

(electrode reduction potential; tendency to get reduced= -tendency to get oxidised)


• General trend along the series: becomes less negative along the series.


Reason; general increase in sum of ionisation enthalpies (IE¹+IE²)


IRREGULARITIES: MORE negative values of Mn, Ni, Zn (munizan)

Reasons for more negative values for Mn, Ni, Zn for E (M²|M)

Note: more negative value of electrode potential= more OP(i.e. tendency to get oxidised)


It WANTS to get oxidised to M² - indicating that its form is more stable/has stable electronic configuration. - possible reasons for Mn and Zn


Whereas for Ni- it has the highest negative hydration enthalpy.

Trends in Electrode potential E(M³|M²)

• shoulda generally increased/become less negative


But there are many irregularities


•Values comparatively more negative;


Sc and Fe ; reflects the stability of their M³ ions. Sc³ has NG configuration whereas Fe³ has d⁵ configuration.


•Values comparatively high/less negative/more positive;


Zn and Mn ; because of their stable configuration in M² ions. Highest value of Zn.

Stability of Higher Oxidation states

Halides


•highest oxidation numbers are achieved in TiX⁴, VF⁵ and CrF⁶


+7 in Mn is NOT represented by simple halides. Instead it's represented by MnO³F.


Beyond Mn, trihalides are NOT found other than FeX³, and CoF³


V⁵ is represented only by VF⁵; other V⁵ halides undergo hydrolysis to form VOX³


•instability of flourides in low Oxidation states (e.g.VX² and CuX)

Cu(II) halides are known except

Iodides.



. Reaction of Cu² with iodide gives Cu²I² [Cu(1) iodide]


Cu(1) compounds are unstable in aq solution and undergo disproportionation to form Cu² and Cu⁰

Why is Cu² more stable than Cu+. Demonstrate with the help of a reaction.

Because Cu² has much more negative hydration enthalpy which compensates for IE² of Cu.



Reaction:


Cu(1) compounds are unstable and undergo disproportionation in aqueous solution to yield Cu² and Cu⁰

Flourine has the ability to stabilise high Oxidation states. State 2 reasons.

• high lattice energy in case of CoF³


• higher bond enthalpy in case of VF⁵ and CrF⁶

Magnetic properties

Whenever a substance is placed in MF, 2 types of behaviours are observed: para and diamagnetism


Most TM ions are paramagnetic: which arises due to presence of unpaired electrons( which have magnetic moment associated with its spin angular momentum and orbital angular momentum ).



• But for compounds of TM of 1st series, contribution of orbital angular momentum is effectively quenched .


This, magnetic moment is determined by number of unpaired electrons ; and calculated by spin-only formula.

Spin only formula

u= √n(n+2) BM (Bohr's magneton)

Formation of complex compounds

Complex compounds: compounds in which metal ions bind a number of ligands(neutral or charged molecules/ions) to form complex species with special characteristics.



•give a couple of God damned examples, will ya! [Co(NH³)⁶]³+



• TM's form a large number of complex compounds. Reasons

Reasons why TM's form a large number of complex compounds.

•availibility of d orbitals for bond-formation


•high ionic charges.


comparatively smaller sizes of metal ions. (In my intuition enables them to bind a number of ligands)


{ In short, availability of d orbitals for bond-formation AND high charge to radius ratio value}

3

What is the most stable oxidation state of all the lanthanoids?


Ln³+

F block elements

Series of elements formed by filling of f orbitals. (The last electron enters the f orbital in these elements)


It consists of 2 series:


lanthanoids(14 elements following lanthanum starts: Cerium and ends with Lutetium)


Actinoids (14 elements following actinium)

Lanthanoids

Members esemble one another more closely than do the member of any other transition series.


They have only one stable oxidation state (Ln³) .


Characteristic feature: lanthanoid contraction;

Points to be mentioned in lanthanoids

electronic configuration


atomic sizes


• oxidation states


• General characteristics -chemical behaviour


Physical properties of Ln

• describe yourself like a narcissist would- soft, white, silvery,


•tarnishes rapidly in this crooked world(i.e. air)


Hardness : very hard, especially Samarium(hard-hearted)


• High MP's: 1000-1200K but Sm has 1623K


•typical metallic lustre


•good conductors(heat and electricity)


Colour: most ions are coloured.(attributed to presence of f electrons)


Magnetic properties: most are paramagnetic except f¹⁴ and f⁰ configurations.

Color of Ln

Many Ln³ ions are coloured except La³ and Lu³.


Absorption bands are narrow.


(Reason: excitation takes place within f level)

Magnetic nature of Ln

All Ln ions are paramagnetic except


•f⁰- La³Ce⁴


•f¹⁴- Lu³Yb²

Ionisation enthalpies of Ln

IE¹- app. 600kJ/mol


IE²- 1200


IE³- discussion indicates the loss of EE imparts stability to empty, half, completely filled f subshell.


Abnormally low IE³- (La G ge d Lu tetium) La, Gd, Lu (lagged Lutetium)



[comparable with those of Ca]

Uses of Ln

•alloy steel production- mischmetall ;


M's


consist of Ln(95%), Fe and other M's and NM's- which in turn is used in Mg-based alloys to produce bullets, shells etc.


Mixed oxides of Ln; employed as catalysts in petroleum cracking.


individual Ln oxides - used as phosphors in tV screens etc