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96 Cards in this Set

  • Front
  • Back
momentum
Ft = mv-mu
F = (mv-mu)/t = m(v-u)/t = ma
impulse = change in momentum
rebound momentum
2mu only if the speed of impact is t equal to the speed of rebound
momentum in an explosion
total momentum is 0
when direction is taken account of
circular motion F=
centripetal force
acting towards centre
mv^2/r
mω^2r
circular motion v=
straight line velocity
2πr/T
2πrf
ωr
angular speed w=
amount of angle travelled per second
2πf
2π/T
centripetal acceleration a=
the acceleration towards the centre of motion
v^2/r
ω^2r
circular motion positive direction ?
towards centre
car on banked track v=
v^2 = gr tanθ
(N+N)sinθ = mv^2/r
(N+N)cosθ = mg
(N+N)sinθ / (N+N)cosθ = v^2/rg
tanθ = v^2/rg
amplitude
maximum displacement from the equilibrium point
Time period
time to complete one full cycle (seconds)
Frequency
the amount of cycles/ oscillations in one second (Hz)
phase difference
2πΔt/T
must be in radians
simple harmonic motion
acceleration is always opposite to direction of displacement
a = -kx a = -(2πf)^2 x
undamped system
Time period / frequency of simple harmonic motion
T = 2π sqrt(l/g)
T = 2π sqrt(m/k)
energy of simple harmonic motion
total energy is always constant
total energy is always constant
energy stored in a spring
0.5kx^2
resonance
when the periodic force is applied at the natural frequency
phase difference of π/2
Bartons pendulums
target pendulum is in resonance π/2 out of phase 
shorter π/2 out of phase 
longer π out of phase
target pendulum is in resonance π/2 out of phase
shorter π/2 out of phase
longer π out of phase
radial field
field lines like spokes on a wheel directed to the centre
uniform field
same magnitude and direction throughout the field
parallel field lines
gravitational potential
work =
mass (m) x potential (v)
therefore potential is the work per unit mass
or energy per unit mass
gravitational potential (v) unit
J/kg
gravitational field
force per unit mass
equipotential gradients
lines where the potential of the field are equal
lines where the potential of the field are equal
potential gradient
change of potential per metre at that point
Δv/Δr
connect g and V
g is the gradient of v 
therefore Δv/Δr = g
g is the gradient of v
therefore Δv/Δr = g
gravitational force
F = G Mm/r^2
gravitational field against distance
g = GM/r^2  as long as r is larger than the radius of the body
g = GM/r^2 as long as r is larger than the radius of the body
geostationary satellites
T =
24 hours
86400 seconds
electric field direction
positive to negative
positive to negative
electric field vector or scaler
vector
electric field strength
force per unit charge
E = F/Q
density of field lines show
the strength of the field
electric potential
work done per unit charge to move it from infinity to that point in the field
unit of electric potential
Volt (v)
1 J/C
(electric) energy can be calculated as
Voltage x charge
electric potential and electric field strength connection
the electric field is the gradient of the electric potential
the electric field is the gradient of the electric potential
equipotential of electric fields
can be a 0 point where there is no potential
can be a 0 point where there is no potential
coulombs law
F = k Qq/r^2
k = 1/4πε
electric field definition
force per unit charge
compare force of gravitational field and electric fields
F = GMm/r^2 = Qq/4πεr^2
compare field strength of gravitational field and electric fields
g = F/m E = F/q
compare units of gravitational field and electric fields
N/kg or m/s^2
N/C or V/m
compare units of potential of gravitational field and electric fields
J/kg Volts (J/C)
radial gravitational field
g = GM/r^2
v = -GM/r
radial electric field
E = Q/4πεr^2
v = Q/4πεr
capacitor
a device designed to store charge with two metal plates separated by an insulator
charge on a capacitor
charge = current x time
C = C/S x S
how to measure capacitance
charge a capacitor through a variable resistor, by varying the resistance keep the current constant. Multiply the current by the time, plot charge against the voltage which is measured through a volt metre on the capacitor. to find the capacitance find the gradient Δq/Δv
capacitance
the charge stored per unit pd
energy stored in a capacitor
E = 0.5QV = 0.5CV^2 = 0.5(Q^2)/c
Area under a voltage charge graph
capacitor discharge
Q = Qe^(-t/RC)
V = Ve^(-t/RC)
I = Ie^(-t/RC)
Q = Qe^(-t/RC)
V = Ve^(-t/RC)
I = Ie^(-t/RC)
Time constant
RC
Resistance x capacitance
Capacitor charging
the charge will go up making the resistance of the capacitor higher so the current will drop
the charge will go up making the resistance of the capacitor higher so the current will drop
magnetic flux density
B - strength of the magnetic field
force per unit length per unit current on a current carrying conductor at right angles to the magnetic field lines
flemings left hand rule
thumb - force 
index - field 
middle - current
thumb - force
index - field
middle - current
force of a magnetic field
F = bIl
simple electric motor
the current is in a different direction on both sides of the coil so the force is in different directions. 
a split ring communicator is needed so the current will change direction on the sides of the wire to i will spin the same direction
the current is in a different direction on both sides of the coil so the force is in different directions.
a split ring communicator is needed so the current will change direction on the sides of the wire to i will spin the same direction
unit of magnet it field B
Tesla T or wb/ or NS/Cm
magnetic flux
magnetic flux density x area
BA
magnetic flux linkage
magnetic flux density x area x number of coils
BAN
force on a moving charge
F = BQv
radius of charge in magnetic field
BQv = mv^2 /r
r = mv/BQ
Thermionic emission
heated metal will give of electrons
what happens when a wire is moved in a magnetic field
an emf is produced
emf produced when ?
when there is relative motion between the magnetic field and a conductor
dynamo rule
thumb - motion 
index - field 
middle - induced current
thumb - motion
index - field
middle - induced current
lenz's law
the direction of the induced current is always such as to oppose the change that causes the current
Faradays law of electromagnetic induction
induced emf in a circuit is equal to the rate of change of flux linkage through the circuit
emf
emf = -N ΔΦ/Δt
transformer equation
Np/Ns = Vp/Vs = Is/Ip
how are transformers made more efficient
core to make the field lines go through the second coil
laminated coil to reduce eddy currents
efficiency of a transformer
IsVs/IpVp x 100
grid system
high voltage low amps
alternating current so magnetic field changes so transformers can be used
rutherford experiment
alpha particles shot at gold foil (all same kinetic energy) 1 in 2000 are deflected
1 in 10000 deflected over 90 degrees
nucleus contains most mass and is positively charged
gold foil in alpha scattering need's to be
thin to stop double scattering and to let alpha particles through
alpha particle in cloud chamber
all easily visible and the same length showing they all have the same kinetic energy
β particles in cloud chamber
wispy tracks that are easily deflected by air molecules, not as easy to see because β particles are less ionising
intensity of gamma source
k/r^2
nhf/4πr^2
activity of radioactive source
number of nuclei that disintegrate per second
unit of activity
becquerel Bq
alpha and beta emission on NZ graph
alpha - looses two N, looses two P
Beta minus - Gains P, looses N
Beta plus - looses P, Gains N
alpha - looses two N, looses two P
Beta minus - Gains P, looses N
Beta plus - looses P, Gains N
metastable state
gamma photon must be emitted to get to ground state
binding energy
work that must be done to separate a nucleus into its constituent particles
mass defect
difference between the mass of separated nucleons and the nucleus
internal energy
sum of kinetic energy's and potential energy's of molecules
Celsius - kelvin
Celsius = kelvin - 273.15
Celsius + 273.15 = Kelvin
specific heat capacity Q =
mcΔt
specific heat capacity
the amount of energy to raise the temperature of a unit mass by 1 kelvin without changing the state
latent heat graph
during phase change there is energy input but no heat change
during phase change there is energy input but no heat change
latent heat of fusion
energy needed to melt a solid at it's melting point
latent heat of vaporisation
the energy needed to vaporise a liquid at it's boiling point
specific latent heat of fusion
energy needed to change the state of unit mass of a substance from solid to liquid without temperature change
specific latent heat of vaporisation
the energy needed to change the state of unit mass of a substance from liquid to vapour without change in in temperature
kinetic theory temperature